Theories, Problems, Solutions

How much energy is required (in Joules) when the temperature of 3.6 grams of liquid water increases by 4 °C ?

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Re: Hot Water

by Malok on Fri 03 Aug 2007 02:46 PM EDT | Profile | Permanent Link

Qwater = m c deltaT

m = 3.6 grams

therefore:

Qwater = 3.6 x 1 cal/gC x 4 C

= 14.4 cal

1 calorie = 4.184 joule

14.4 cal x 4.184 joule/cal = 60.2496 joule

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