How many positive integers can be formed from the digits 1, 2, 3, and 4 if no digit is repeated in any one integer?
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Re: Positive Integers
by
Dante
on Sat 15 Oct 2005 03:36 PM EDT | Profile | Permanent Link
The answer is 64 = 4+12+24+24. Here is another question. Given the "digits" 1, 2, ..., n, how many distinct 3-digit (triplets) may be formed from these, such that no two digits appear in more than one triplet?
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